A charge Q is placed at a distance of 4R above the center of a disc of radius R. The magnitude of flux through the disc is φ φ . Now a hemispherical shell of radius R is placed over the disc such that it forms a closed surface. The flux through the curved surface (taking direction of area vector along outward normal as positive), is -
Text Solution
Verified by ExpertsThe correct answer is:
C
For the closed surface made by disc and hemisphere
qin = 0
φ φ net = 0
φ φ disc + φ φ H.S = 0
φ φ HS = – φ φ disc = – φ φ
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